CSIR NET (Physics)

CSIR NET 2018 December Physical Sciences: converting a RS flip-flop into a JK flip-flop. Photo Credit: mdashf.org

CSIR NET 2018 December Physical Science Solutions Part-B

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The CSIR NET 2018 held on December 16: Indian
Assistant Professor and PhD scholarship exam
solution, prepared by me. The answers and
detailed explanations are available for 18
out of 25 questions of Part-B. The detailed
explanations and answers to Part-A is also
available, see link below.

Please point out any inadvertent errors.

(this is entirely free stuff: help spread the word)

The article aims to make the best attempt at finding the answers for the recently concluded 2018 CSIR NET. Detailed explanatory answers for physical sciences section ( part-B ) is available ( for 18 out of 25 questions at the moment ). Also full explanation based solutions to part-A is available, check link above.

Q – 21. Consider the decay A → B + C of a relativistic
spin 1/2 particle A. Which of the following statements
is true in the rest frame of the particle A?

1. The spin of both B and C may be 1/2.
2. The sum of the masses of B and C is greater than
the mass of A.
3. The energy of B is uniquely determined by the
masses of the particles.
4. The spin of both B and C may be integral.

Explanation: obviously the second option is incorrect as it violates conservation of energy in relativistic kinematics, rest-masses of the product particles can not be more than that of the parent particle. Option 3 is explained with a diagram. The value of the energy of one of the daughter particle ( B ) is determined uniquely as evinced by the given formula for the same.

In a two body relativistic decay in the parent rest frame: EB = ( MA2 – MC2 + MB2 ) / 2 MA

Also the other options talk about the spin of the particles but we need not bother since option 3 is the correct option.

CSIR NET 2018 December Physical Sciences: answer to question 12 Venn diagram shows that number of students who took biology but not chemistry is number of students who took biology minus number of students who took both biology and chemistry photo credit: mdashf.org

The CSIR NET 2018 December solutions

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The article aims to make the best attempt at finding the answers for the recently concluded 2018 CSIR NET. Detailed explanatory answers are available to 19 out of  20 questions in Part A, at the moment. Only physical sciences paper part B and C will be added.

CSIR NET 2018 December physical sciences
Part A

Q – 1. A tourist drives 20 km towards east, turns
right and drives 6 km, then drives 6 km towards west.
He then turns to his left and drives 4 km and finally
turns right and drives 14 km. Where is he from his
starting point?

1. 6 km towards east
2. 20 km towards west
3. 14 km towards north
4. 10 km towards south

Q – 2. In an examination 100 questions of 1 mark
each are given. After the examination, 20 questions
are deleted from evaluation, leaving 80 questions
with a total of 100 marks. Student A had answered
4 of the deleted questions correctly and got 40
marks, whereas student B had answered 10 of the
deleted questions correctly and got 35 marks.
In this situation

1. A and B are equally benefited.
2. A and B lost equally.
3. B lost more than A.
4. A lost more than B.

Q – 3. A circular running track has six lanes,
each 1 m wide. How far ahead ( in meters )
should the runner in the outermost lane
start from, so as to cover the same distance
in one lap as the runner in the innermost lane?

1. 6 π 2. 10 π
3. 12 π 4. 36 π

How best to prepare for UGC, CSIR-NET

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If you are to come out of a NET that traps you. Stratagem.

This article is purported to be helpful towards those who take Indian “after the university” entrance exam known as NET (National Eligibility test governed by CSIR; Council of Scientific and Industrial Research) which is held twice every year.

NET for science subjects is known as CSIR-NET and arts/humanities as UGC-NET. They are conducted at different times and by different agencies.

Manmohan sir, I want to qualify net. … any suggestions ?

Find an algorithm at the end for a quicker assimilation of the strategies given here. Both pdf and jpg are available.

I am assuming you will take the test in June 2018.

Solve 10 previous papers thoroughly.

Make a categorization of subject wise weightage: eg mathematical physics, quantum mechanics, thermodynamics etc.

Set yourself a good score based on what you think you can certainly achieve. Make a 15% increase and make that your target.

See your strongest subjects and make a plan which ones you want to be thoroughly prepared about so you can arrive your target.

Never attempt a question, unless you are very sure of it. Negative marks in net can ruin your chances. (By attempt I mean: select the choice)

Decide in which section you want to score how much.

In section A (total marks 30) try to achieve full marks, except a few daunting questions. Getting 22 (11 questions right, assuming no negative score) seems a good idea. In section